A heap of wheat is in the form of a cone whose diameter is 10.5 m and height is 3 m. The heap is to be covered by canvas to protect it from rain. Find the area of canvas required.
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10
l=√10.5/2+3
=6.05m
ar.of canvas required = l.s.a of cone
= πrl
=22/7×5.25×6.05
=99 m
=6.05m
ar.of canvas required = l.s.a of cone
= πrl
=22/7×5.25×6.05
=99 m
Answered by
2
I=sqrt 10. 5/2+3
=6.05m
Ar of canvas req.=I. s.s.a of cone
=22/7×5.25×6.05
=99m
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