Question

A heat appliance has resistance 115 resister .if 2A current flow through it . what is the power of appliance . If it works for 5 minutminute find the genereated

Answer 1

Answer:

Henceforth, the power of appliance = 460 W

Explanation:

Given,

Resistance of appliances, R = 115 ohms

Current of appliance, I = 2 A

Let the potential difference of the appliance be V. Then,

By ohm's law, we know that,

Resistance = Potential Difference / Current

=> R = V/I

By applying values, we get,

=> 115 = V / 2

=> V = 230

Hence, potential difference of the appliance = 230 V

Now, we know that,

Power = Potential Difference × Current

=> P = V × I

=> P = 230 V × 2 I

=> P = 460 VI

=> P = 460 W

Henceforth, the power of appliance = 460 W

Answer 2

Answer:

Electric Power = 460 W , Heat Generated = 138 kWh

Explanation:

Let, R= 115 Ω

i = 2 A

t = 5 minutes = (5*60) seconds = 300 seconds

Now,

Electric Power = (i²)R

= ( 2²) 115

= 4*115

= 460 Watt

Now,

Heat Generated = P*t

= (460*300)

_________ kWh

1000

= 138000

_______ kWh

1000

= 138 kWh

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