Physics, asked by rsmdeepika2111, 9 months ago

A heat engine has an efficiency 'n'. When
the temperatures of source and sink are
400K and 300K. If temperature of source
and sink are each decreased by 100K.
Then the efficiency of the engine is​

Answers

Answered by pancypoppy1234
0

Answer:

η increases.

Explanation:

η=1=1−T1−T2T1

When T1 and T2 both are decreased by 100 K each, (T1−T2) stays constant . T1 decreases

η increases.

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