A heat engine performs 200J of work in each cycle and has efficiency of 20% . How much heat is absorbed ?
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Answered by
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we know efficiency =1-Q2/Q1(or =W/Q1) As eff. =20% therefore efficiency =20/100 =2/10 and work performed,W =200J(GIVEN) thus 2/10 (eff.)= 200/Q1 WHICH Implies Q1= 1000J now heat absorbed,Q2= Q1-W=1000-200=800J WHICH IS THE HEAT ABSORBED.
areebah:
The answer is 1000Joules . Not 800j :/
sorry u r right the answer is Q=1000J
So how come ? Thats what im confused in ? :/
Hey leave i just got the answer already . Thanks . Bless you
Answered by
26
Answer:
A
Explanation:
A Heat engine is performs 200J of work in each cycle and has efficiency of 20 %. Find (a) How much heat is absorbed? (b) How much is Expelled??
W = 200J
E =20 % = 20 ÷100 = 0.2
E = 0.2
Q1 = ?
Q2 = ?
Solution :
E = W/Q1
Crossing = EQ1 =w
Putting values
0.2 × Q1 = 200
0.2 --> Multiply and divide by both side
Q1 = 200/0.2
Q1 = 1000J
Now find the Q2
Q2 = Q1 - W
Q2 = 1000 - 200
Q2 = 800 J
This is Correct way
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