Question

A heat engine work at the 500. KW the efficiency of the engine is 40℅ .Calculate the loss of heat per hout

Answer 1

Answer:

fjsiehxowhdjebcjebciehdjddbxdjdbhejdje

Answer 2

Answer:

The lost of heat per hour is 108 × 10^4 K J/s

Explanation:

A heat engine perform work at the rate of 500 KW.

Rate of doing work is 500 KW = 500 K J/s

The efficiency of engine is 40 % . It mean 60 % of energy is lost as heat.

$60\% \: of \: 500 \:$

$\frac{60}{100} \times 500 \times 3600$

$1080000 = 108 \times {10}^{4}$