Question

A heater at220v boils avolune of water in 5 min time if the heater is operated at 110 v the same volume of water will boil in 10n minute

Answer 1

As total energy must be conserved

W1=w2 w=v^2/R*t

220*220/R *5*60=110*110/R *t

T we need to find

R R gets cancel

4*300=T

1200 sec =T

20minutes

10*2 minute n=2

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