A heater boils 1 kg of water in time t1 and another heater boils the same water in time t2. If both the
heaters are connected in parallel, the combination will boil the water in time
Answers
Given:
A heater boils 1 kg of water in time t1 and another heater boils the same water in time t2.
To find:
If both the heaters are connected in parallel , the combination will boil the water in time
Solution:
From given, we have,
A heater boils 1 kg of water in time t1 and another heater boils the same water in time t2.
We use the below formula to calculate the time,
P = Q/t .....(1)
The time taken by boiler 1 = t₁
⇒ P₁ = Q/t₁
The time taken by boiler 2 = t₂
⇒ P₂ =Q/t₂
If the boilers are connected in parallel, then we have,
P = P₁ + P₂
P = Q/t₁ + Q/t₂
P = Q (1/t₁ + 1/t₂)
P = Q (t₁ + t₂/t₁t₂) ......(2)
comparing equations (1) and (2), we get,
t = t₁t₂/(t₁ + t₂)
The combination will boil the water in time is t₁t₂/(t₁ + t₂)
Answer:
The correct answer is t1+t2
Explanation:
hope the answer is helpful for you
