Physics, asked by RajlaxmiKashyap, 1 year ago

a heater coil of resistance 40ohm carries a current I.if the power of the heater is 1kWh,calculate the magnitude of I.

RajlaxmiKashyap: pl help kariyei na

Anonymous: I can take power as 1kw and do... check your book once again though

Anonymous: I have solved it.. but there might be some minor mistake.. because power cant be in kwh and if you take kw, you get different answer.

RajlaxmiKashyap: Urav bhaiya in my book the answer is5 A.n kWh is may b printing mistske..nywayz..thnk u ..plz help me in my numerical problems i'll send da questions.. thnx thnx thnx thnx thnx..

Anonymous: okay so in your book they have taken kw, with means 1000 watts.. in my question below, take it as 1000 watts and you will get the answer.

Anonymous: I have corrected it.

Anonymous: and your'e welcome.

RajlaxmiKashyap: ooo.bhayiya u r the bst. thnk u once more..by the way i hv sent one more question

RajlaxmiKashyap: if i hv problem will u hlp me..bhaiya

Anonymous: yea sure, even im in tenth :p

Answers

Answered by Anonymous

Power = $current^{2}$ × resistance.
1000 w = $I^{2}$ × 40 [∵1kw = 1000 w]
$I^{2}$ = 25
I = $\sqrt{25}$

I = 5 ampere.

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