a heater of 1000w is connected to the 250v. calculate the electrical energy ( kwh) when heater is operated in2h
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Answer:
POWER = 1000 WATT
CHANGE IN KWH
1000/1000=1KWH
E=P*T
E=1*2
E=2KWH
FOR 30 DAYS IT will be
2*30=60kwh
the cost of energy is 5rupees per kwh
5*60
=rs 300
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