Question

A heater of resistance 10ohms draws 10A current the electric power it consumes is ?
A) 1watt B) 100watt C) 1kilowatt D) 100kilowatt .​

Answer 1

• ✿ C) 1kilowatt.

STEP BY STEP EXPLAINATION :-

☆ Given here,

• I = 10 A

• R = 10Ω

✷ By ohm's law ,

→ v = IR

• Inserting values to find v (potential difference)

→ v = 10A×10Ω

→ v= 100 v

NOW , we know power equals to potential difference square by resistance therefore applying the formula we get ,

→ p= v²/R

→ p= (100v)²/10

→ p= 10000v/10Ω

→ p = 1000 W

or

→ p= 1 kilowatt .

Therefore the resistance of the heater 10Ω drawing the current of electric power 10A consumes 1 kilo watt of power .

HOPE IT HELPS ❣️

Answer 2

Answer:

(C)The electric power consumed by the heater is 1kW

Explanation:

Given that,

A heater of resistance 10ohms draws 10A current.We are required to find the power consumed by the electric heater.

The power consumed by the electric heater is the product of its voltage and current.Therefore, $P=Vi$

As voltage is the product of electric current and the resistance we can rewrite the above relation as $P=(iR)i=i^{2}R$$P=(iR)i=i^{2} R$

Substituting the given values of electric current and resistance in the above equation,we get-

$P=10^{2} \times10=1000W=1kW$

Therefore,The electric power consumed by the heater is 1kW

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