Question

A heater of resistance 50 Ω works on 200 V mains for 2 hours a day. Find the energy consumed by heater in kWh in a week​

Answer 1

For a heater -

$\large \underline \bold{Given :-}$

$\sf{resistance \: (R) = 50}$Ω

$\: \:$$\sf{Voltage \: (V) = 200 \: volt}$

$\: \: \:$$\sf{time \: (t) = 2 \: hours/day}$

$\large \underline \bold{To \: Find :-}$

$\sf{how \: much \: energy \: consumed \: by \: heater \: in \: a \: week \: ?}$

$\large \underline \bold{Usable \: Formulas :-}$

$\: \: \: \: \: \:$$\sf{P =\dfrac{V^{2}}{R}}$

$\: \: \: \: \:$$\sf{Energy = power\times Time}$

$\large \underline \bold{Solution :-}$

Firstly ,

$\: \: \: \: \: \:$$\sf{P =\dfrac{200\times 200}{50}}$

$\: \: \: \: \: \:$$\sf{P = 200\times 4}$

$\: \: \: \: \: \:$$\sf{P = 800 \: watt}$

$\: \: \: \: \: \:$$\sf{P = 0.8 \: KW}$

Now ,

energy consumption for a week(7 days) -

$\: \: \: \:$$\sf{Energy = P\times t}$

$\: \: \: \:$$\sf{E = 0.8\times 14}$

$\: \: \: \:$$\sf{E = 11.2 \: KWh}$

Answer 2

Answer:

11.2KWH. Please mark me brainlist and thanks ❤️