Question

A heater of resistance 50 Ω works on 200 V mains for 2 hours a day. Find the energy consumed by heater in kWh in a week​

Answer 1

Answer:

Energy consumed by heater in kWh in a week will be 11.2 kWh.

Explanation:

Given:

• Resistance (R) = 50 Ω

• Potential difference (V) = 200 V

• Time (t) = 2 hrs each day.

Time is 2 hrs each day. So, time for 1 week = 2 × 7

= 14 hrs.

To find:

Energy consumed by water in kWh in a week.

Solution:

Energy consumed in a week

= P × t

= 800 W × 14 h

= 11200 Wh

So, energy consumed in kWh

= 11200/1000 kWh

= 11.2 kWh.

Answer 2

Answer:

11.2kwh will be the correct answer