Physics, asked by Apandey9047, 6 months ago

A heater rated as220v,880w is the current drown by the neater when connented to a220v DC main? calculate the resistance of the heater.

Answers

Answered by Anonymous
4

 \small \underline \bold{For \: a \: heater -}

 \large \underline \bold{Given :-}

\: \: \: \: \:  \small \bold{power \: (P) = 880 \: W}

\: \: \:  \small \bold{voltage \: (V) = 220 \: volt}

 \large \underline \bold{To \: Find :-}

 \small \bold{Calculate \: the \: resistance \: of \: the \: heater \: ?}

 \small \underline \bold{Usable \: Formula :-}

\: \: \: \: \:  \small \bold{Power \: (P) =\dfrac{V^{2}}{R}}

 \large \underline \bold{Solution :-}

 \small \bold{On \: Using \: the \: above \: formula -}

\: \: \: \:  \small \bold{R =\dfrac{V^{2}}{P}}

\: \: \: \:  \small \bold{R =\dfrac{220\times \cancel{220}}{\cancel{880} \: 4}}

\: \: \: \:  \small \bold{R =\dfrac{220}{4}}

\: \: \: \:  \small \bold{R = 55} Ω

 \small \bold{The \: heater \: has \: a \: resistance \: of \: 55}Ω .

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