A heater wire whose power is 4KW is connected to 220 V source calculate:- (i) Electric current in the circuit (ii) Resistance of heater (iii) Energy consumed in 2 hours. pleasee pleasee pleaseeee answer asap..thanks
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Power = 4KW = 4000 W
Volt = 220
Electric power , P=VI
(I)After putting values, I = 18.18 A
(II)R denotes resistance here ,V= IR
R= V/ I= 220 V/ 18. 18 A= 12. 1012 ohm.
(III) Power= 4000 W= 4000 J/ s
So, in 2 hours energy in kWh is = 4000J/ s * 3600 * 2/( 3600000)= 8 kWh
BrainlyYoda:
Please mark as brainliest answer
in step II),,,, R = V^2 /P = 220^2/4000 = 12.1 Ohm exact....
you used an approx or rounded off number 18.18 to calculate R... so there is an approx value obtained. Preferable to use V^2/R directly, if it is possible, instead of using a rounded off number.
But the answer should be as accurate and as precised as possible.
precise answer is 12.1 exactly.... 12.1012 is not correct...
but you will get marks no problem... but what i pointed out is : use the input data directly to compute the answer...
OK Sir
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