Question

A heater working in 240v mains consumers 0.5A current (a) calculate the quantity of charge flowing through the heater coil(b) calculate the resistance of the heater.(c) find the quantity of heat generated in the heater when worked for 5 minutes

Answer 1

Potential difference (V) = 240 V

Current (I) = 0.5 A

Let 'R' be the resistance.

Let 'H' be heat generated.

(a) According to the definition, one ampere means one coulomb of charge flowing per second.

Hence, 0.5 A implies 0.5 C charge per second.

(b) From Ohm's law,

V = IR

R = V/I = 240/0.5 = 480 ohm

(c) H = $I^{2} Rt$

H = 0.5*0.5*480*300 = 0.25*144000 = 36,000 J