Question

A heating appliance has a
resistance of 115 ohm If 2A
current flows throught for 10 min
What is the heat
heat developed in
the
appliances​

Answer 1

Given:

• Resistance, R = 115 ohm

• Current, I = 2 A

• Time, t = 10 min = 10 × 60 = 600 s

To be calculated:

Calculate the heat?

Formula used:

Heat = I²Rt

Solution:

We know the resistance, current and time taken of a heating appliance. So, we can find out by using the formula :

Heat = I² × R × t

★ Substituting the values in the above formula,we get

Heat,H = ( 2 )² × 115 × 600

= 4 × 115 × 600

= 460 × 600

= 276,000 Joules

Additional information :

V = Potential difference, I = Current , R = Resistance

Q = Charge , t = time taken , P = power ,W = work

• V = IR

• I = Q/t

• V = W/Q

• P = V²/R

Answer 2

GiVeN :-

→ A heating appliance has a  resistance of 115 Ω. 2A  current flows through the appliance for 10 min.

• Resistance, R = 115 Ω
• Current, I = 2 A
• Time, t = 10 mins = 600 s

To DeTeRmInE :-

The heat energy developed(H) in the appliance for 600 s.

AcKnOwLeDgEmEnT :-

Joule's law of heating states that when a current 'I' passes through a conductor of resistance 'R' for time 't' then the heat developed in the conductor is equal to the product of the square of the current, the resistance and time.

$\bullet$ H = I²Rt.

SoLuTiOn :-

Substituting the known values in the above formula :-

$\rm{\hookrightarrow H=(2)^2\times115\times600}\\\\\rm{\hookrightarrow H=4\times600\times115}\\\\\rm{\hookrightarrow H=2400\times115}\\\\\boxed{\boxed{\rm{\hookrightarrow H=276000\ J}}}$

Hence, 276000 J or 276 kJ of heat energy is produced in the heating appliance for 10 mins (or 600 s).