Question

A heating appliance has a resistance of 115 ohm if 2A current flows through it for 10 minutes. what is the heat devoloped in the appliance

Answer 1

$\huge{\underline{\pink{\tt{Given,}}}}$

• A heating Appliance has a Resistance of 115 ohm.
• If 2 A Current flows through it .
• Time = 10 Minutes ( Convert into Second - 10 × 60 = 600 Second)

$\huge{\underline{\pink{\tt{To \ Find,}}}}$

• The Heat Developed in the Appliance .

$\huge{\underline{\pink{\tt{Formula\:Used:}}}}$

• $\underline{\boxed{\sf{Heat = (Current)^{2} \times Resistance \times Time}}}$

$\huge{\underline{\pink{\tt{Solution :}}}}$

$\bigstar$ Firstly, We know About Joule's Law of Heating :

$\longrightarrow$ This Law Define that When a Current (I) Passes through a Conductor of Resistance (R) For Time (t) then the heat produced in the Conductor is Equal  to the Product of the Square of the Current , Resistance and Time.

Now Solve this Question with the Help of this Law :

$\mapsto \boxed{\sf{Heat = I^{2} \times R \times t}}$

$\mapsto \sf{Heat = (2)^{2} \times 115 \times 600}$

$\mapsto \sf{Heat = 4 \times 115 \times 600}$

$\mapsto \sf{Heat = 600 \times 460}$

$\mapsto \boxed{\sf{Heat = 276,000\:Joules \ or \ 276\:kJ}}$

Therefore,

$\longrightarrow$ 276,000 Joules of Heat Energy Developed in the Appliance.

$\rule{200}2$

Answer 2

$\huge\mathfrak{Answer:}$

Given:

• The resistance of a heating appliance is 115ohm.
• 2A current flows thorough this electrical appliance for 10 minutes.

To Find :

• We need to find the amount of heat developed in the appliance.

Solution:

We have been given the resistance of a heating appliance as 115ohm and 2A current flows thorough this electrical appliance for 10 minutes.

10 minutes = 10 × 60 seconds = 600 seconds.

We know that,

$\sf{heat = ( {current)}^{2} \times (resistance) \times time}$

$\mapsto\sf{heat = {I}^{2} \times R \times t}$

Substituting the values, we have

$\sf{heat = {2}^{2} \times 115 \times 600}$

$\implies\sf{heat = 4 \times 115 \times 600}$

$\implies\sf{heat = 460 \times 600}$

$\implies\sf{heat = 276000joules}$

Hence, amount of heat developed in the appliance is 276000J.