A heating coil has a resistance of 3092. It is designed to operate on 220 V. What
electric energy in joules is supplied to the heater in 20 s?
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Answer:
313 J
Explanation:
Energy = Power x Time
Power = Voltage²/Resistance = 220²/3092 = 15.65 Watts
Energy = 15.65 x 20 = 313 Joules
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