Question

a heating coil is cut into two halves and both are joined in parallel to the same source.the power liberated is 400 W.Rate of the original coil may be​

Answer 1

Answer:

P = 100W. (power rating) V = 200V. ( voltage supply) thus resistance of the coil: P = V2 / R thus R = 40000/100 = 400 ohm hence of the two new parts produced, new resistance of each part, R' = 200 ohm each on parallel connection, net resistance: 1/Rt = 1/R' + 1/R' hence Rt = R'/2 = 100 ohm and the new power rating, P = V2 /Rt = 40000/100 = 400 W

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