A heating coil of resistance 10 volt takes a current of 2 ampere, the heat developed by is in 5 second s is
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Given : A heating coil of resistance 10 volt takes a current of 2 ampere,
To Find : the heat developed by is in 5 second s is
Solution:
Voltage = 10 V
Current = 2 A
Heat = VIt = 10 * 2 * 5 = 100 Joule
if Resistance is 10 Ω
Heat = I²Rt
= ( 2)² * 10 * 5
= 200 Joule
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