Physics, asked by jayantkatri2435, 1 year ago

A heating element using nichrome connected to a 230 V supply draws an initial current of 3.2 A which settles after a few seconds to a steady value of 2.8 A. What is the steady temperature of the heating element if the room temperature is 27.0 °C? Temperature coefficient of resistance of nichrome averaged over the temperature range involved is 1.70 × 10–4 °C–1.

Answers

Answered by abhi178
4

answer : 867°C

at the room temperature 27°C , the resistance of the heating element is R_{27^{\circ}}= \frac{230}{3.2}=71.875\Omega

[ according to Ohm's law, V = IR , so , R = V/I ]

at the steady temperature t°C , the resistance , R_t=\frac{230}{2.8}= 82.143\Omega

now, use the relation, R=R_0[1+\alpha(T-T_0)]

here, R=R_t = 82.143\Omega

R_0=R_{27^{\circ}}=71.875\Omega

\alpha=1.7\times10^{-4}/^{\circ}C

now, 82.143 = 71.875 [1 + 1.7 × 10^-4(t - 27)]

⇒82.143 - 71.875 = 71.875 × 1.7 × 10^-4(t - 27)

⇒ 0.084 × 10^4 = t - 27

⇒ 840 + 27 = t

⇒ t = 867°C

hence, temperature = 867°C

Answered by Anonymous
243

\huge \underline \mathrm \purple{Question↣}

A heating element using nichrome connected to a 230 V supply draws an initial current of 3.2 A which settles after a few seconds to a steady value of 2.8 A. What is the steady temperature of the heating element if the room temperature is 27.0 °C? Temperature coefficient of resistance of nichrome averaged over the temperature range involved is 1.70 × 10–4 °C^(-1)

\huge \underline \mathrm \green{Answer↣}

In the given problem,‎

The supply voltage is  \bold{V = 230 V}

The initial current drawn is  \bold{I_{1} = 3.2 A}

Consider the initial resistance to be  \bold{ R_{1}} , which can be found by the following relation :‎

⠀⠀⠀⠀⠀⠀⠀⠀ \Large \boxed{ \bold{  \:R _{ 1 } = \frac{ V }{ I }}}

Substituting values, we get‎ ;

⠀⠀⠀⠀⠀⠀⠀⠀ \Large\sf{ : \implies \: R _{ 1 } = \Large{ \frac{ 230 }{ 3.2 }}}

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀ \Large\sf\red{: \implies \: R _{ 1 }  = 71.87 Ω}

Value of current at steady state ,  \bold{ I_{2} = 2.8 A}

Value of resistance at steady state  \bold {= R_{2}}

 \bold{R_{2}} can be calculated by the following equation :‎

⠀⠀⠀⠀⠀⠀⠀⠀ \Large\sf{ : \implies \: R _{ 2} = \Large{\frac{ 230 }{ 2.8 }}}

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀ \Large\sf\red{: \implies \: R _{ 2 }  = 81.14Ω}

The temperature coefficient of nichrome averaged over the temperature range involved is  \bold{ 1.70 x 10^{– 4} ° C^{ – 1}}

Value of initial temperature of nichrome ,  \bold{T_{1} = 27.0 ° C}

Value of steady state temperature reached by nichrome  \bold { = T_{2}}

This temperature  \bold {T_{2}} can be obtained by the following formula :

⠀‎

‎⠀⠀⠀⠀ \boxed{\boxed{ \Large\sf{ \alpha = { \frac{ R _{ 2 } – R _{ 1 }}{ R _{ 1 } \left ( T _{ 2 } – T _{ 1 }\right )}}}}}

⠀⠀⠀⠀⠀⠀⠀⠀ \bold{ \to \:  T_{2} - 27 =  \Large{\frac{82.14 - 71.87}{71.87(1.7  \times 10^{ - 4})}} }

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀ \bold{ \to \:  T_{2} - 27 =  840.5}

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀ \bold{ \to \:  T_{2} =  840.5 + 27}

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀ \large{\bold\red{ \to \:  T_{2} =   {867.5 ° C}}}

ʜᴇɴᴄᴇ, ᴛʜᴇ sᴛᴇᴀᴅʏ ᴛᴇᴍᴘᴇʀᴀᴛᴜʀᴇ ᴏғ ᴛʜᴇ ʜᴇᴀᴛɪɴɢ ᴇʟᴇᴍᴇɴᴛ ɪs 867.5 °C

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