A heavy block is slide across a rough floor with an initial speed of 4m/s . it stops moving after 8 secs . if the average resisting force of friction is 10N the mass of the box I kg is
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u=4m/s
t=8s
v=0
now , v=u+at
0=4+8a
a=1/2 m/s2 ---(1)
Now F=ma
taking F as frictional force ,
10=m x 1/2
m=20kg
hope this help you:)
t=8s
v=0
now , v=u+at
0=4+8a
a=1/2 m/s2 ---(1)
Now F=ma
taking F as frictional force ,
10=m x 1/2
m=20kg
hope this help you:)
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