Question

a heavy block of mass 625 kg is suspended by a cable is moving downwards with an initial velocity of 7.3 m/s . if the tension in the cable as the block comes to rest is 5000 n , calculate the distance travelled by the block

Answer 1

Answer:

3.33 m

Explanation:

M= 625kg

u= 7.3m/s

F= 5000N

S=?

v=0( as it is suspension by cable)

A=?

F=ma

5000= 625*a

a= 5000/625 =8m/s2

V^= U^+2as

0=7.3^+2*8*s

0=53.29+16*s

-53.29=16*s

53.29/16=s

s= 3.33m