Question

a heavy body is dropped from the top of a tower find the displacement covered by the body in the first 2 second interval(g=10m/s^2)​

Answer 1

Answer:

The displacement of body is - 2 Meter.

Explanation:

To find:

The displacement covered by the body in the first 2 second interval.

Given that,

The Initial velocity should be 0m/s because that heavy body.

Hence,

=> Initial velocity {u}= 0m/s.

=> Time taken{t} = 2 seconds.

=> The gravitational acceleration {g} = -10 m/s²

We know that,

Gravitational equation of motion,

$\sf\bigstar ut +\dfrac{1}{2} gt^2=h \bigstar$

Here, 'h' stands for Displacement in the given time interval.

Plug the given values in Equation,

$\sf =>h = 0(2) +\dfrac{1}{2}\times(-10)(2)(2)\\\ =>h = 0 + -2.\\\ =>h =-2.$

Hence,

Displacement of the body in first 2 seconds  -2 meter.