Question

A heavy body of mass 25 kg is to be dragged along a horizontal plane (u = 1/
$\sqrt{3}$
). The least force
required is
(1) 25 kgf
(2) 2.5 kgf
(3)12.5 kgf
(4) 25/
$\sqrt{3}$
kgf
​

Answer 1

Answer:

12.5 kgf is the correct answer..

Answer 2

The least force is 12.5 kgf.

(3) is correct option.

Explanation:

Given that,

Mass of object = 25 kg

Coefficient of friction $\mu=\dfrac{1}{\sqrt{3}}$

We need to calculate the angle

Using formula of angle

$\tan\theta=\dfrac{1}{\sqrt{3}}$

$\theta=\tan^{-1}(\dfrac{1}{\sqrt{3}})$

$\theta=30^{\circ}$

We need to calculate the least force

Using balance equation

$N=mg-F\sin\theta$

$F_{min}=\dfrac{\mu mg}{\cos\theta+\mu\sin\theta}$

Put the value into the formula

$F_{min}=\dfrac{\dfrac{1}{\sqrt{3}}\times25\times g}{\cos30+\dfrac{1}{\sqrt{3}}\times\sin30}$

$F_{min}=12.5\ kgf$

Hence, The least force is 12.5 kgf.

Learn more :

Topic : Least force

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