A heavy box of mass 25 kg is placed on a horizontal surface. If the coefficient of friction between the box and the horizontal surface is 0.25 , calculate the force of kinetic friction. Also calculate the acceleration produced under a force of 196 N applied horizontally?
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Answer:
kinetic friction = 0.25 ×N
= 0.25 × 25×9.8
=61.25
acceleration = F/m
= 196/25
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