Question

A heavy mass is attached to a thin wire and is whirled in a vertical circle. The wire is most likely to break
(a) when the mass is at the highest point.
(b) when the mass is at the lowest point
(c) when the wire is horizontal
(d) at an angle of cos⁻¹(1/3) from the upward vertical.

Answer 1

Answer ⇒ Option (b).  When the mass is at the lowest point.

Explanation ⇒ The Force acting on the Particles will be maximum in case of the Vertical circle when the Force acting will be in the direction of its tension force of string.

When this situation arises then,

Tension (T) = mv²/r

∴ Force will be maximum at this position and there will likely be more chances to break.

This case will be there when the mass is at the lowest position.

∴ Option (b). is correct.

Hope it helps.

Answer 2

Answer:- the correct ans is option

(b).  When the mass is at the lowest point.

Explanation=> If the velocity of the mass is a maximum at the bottom, then the string experiences tension due to both the weight of the mass and the high centrifugal force. Both these factors weigh the mass downwards.

The tension is therefore, maximum at the lowest point, causing the string to most likely break at the bottom. 

Tension (T) = mv²/r

Force will be maximum at this position and there will likely be more chances to break.

This case will be there when the mass is at the lowest position.

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@GauravSaxena01