Question

A heavy nucleus X of mass number 240 and binding energy per nucleon 7.6 MeV is split into two fragments Y and Z of mass numbers 110 and 130 . the binding energy of nucleons in Y is 8.5 MeV per nucleon . Calculate the energy Q released per fission in MeV.

Answer 1

The energy Q released per fission is 9.9 MeV

Explanation:

Given that:

• X (A = 240)
• BE/nucleon= 7.6 MeV/nucleon undergoes fission to release two daughter nuclei.
• Y (A=110) and Z (A = 130) with BE/nucleon of both being 8.5 MeV/nucleon.

For the fission reaction.

Total BE of X= 240 x 7.6 = 1824 MeV

Total BE of (Y+Z) = (110+130) x 8.5 = 2040 MeV

Energy released in the fission = 2040 - 1824 = 216 MeV

Energy released per fission = 216/240= 9.9 MeV

Thus the energy Q released per fission is 9.9 MeV

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