A heavy nucleus X of mass number 240 and binding energy per nucleon 7.6 MeV is split into two fragments Y and Z of mass numbers 110 and 130 . the binding energy of nucleons in Y is 8.5 MeV per nucleon . Calculate the energy Q released per fission in MeV.
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The energy Q released per fission is 9.9 MeV
Explanation:
Given that:
- X (A = 240)
- BE/nucleon= 7.6 MeV/nucleon undergoes fission to release two daughter nuclei.
- Y (A=110) and Z (A = 130) with BE/nucleon of both being 8.5 MeV/nucleon.
For the fission reaction.
Total BE of X= 240 x 7.6 = 1824 MeV
Total BE of (Y+Z) = (110+130) x 8.5 = 2040 MeV
Energy released in the fission = 2040 - 1824 = 216 MeV
Energy released per fission = 216/240= 9.9 MeV
Thus the energy Q released per fission is 9.9 MeV
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