Question

A heavy object is dropped from a vertical distance of 12.0 m above the ground What is the speed of the object as it hits the ground (g=9.8m/s²)​

Answer 1

Answer:

s=12.0m

g=9.8m/s²

v²-u²=2as

v²=2as+u²

=(2×9.8×12)+0²

=24×9.8

v² =235.2

v=root of 235.2

v =15.33m/s

therefore the velocity of the object before it touches the ground = 15.33m/s

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