Question

A heavy particle is tied ot the end A of a string of length 1.6m. Its other end O is fixed. It revolves as a conical pendulum with the string making 60^(@) with the vertical. Then (g=10m//s^(2))

Answer 1

Answer:

1.Since,partical revolves with uniform velocity.

radial force is provided by horizontal components of Tension.

T sin(60)=mw2r

T sin(60)=mw2lsin(60)

T=mw2l

2.Also, Vertical component of tension is balanced by 'mg'.

Tcos(60)=mg

mw2lcos(60)=mg

w=underroot2g/l

3.Then timeperiod

T=2pie/w

2pieunderroot l/2g=2pieunderroot 1.6/2×10

2underroot2pie/5×8