Question

A heavy particle of weight W , attached to a fixed point by a light inextensible string , describes a circle in a vertical plane. The tension in the string has values mW and nW respectively when the particle is at the highest and the lowest points of its path . Show that n = m + 6.

Answer 1

Answer:

Step-by-step explanation:

v°= velocity at lowest point.

Tb= tension at bottom = mw

Tt= tension at top = nw

=> mw + w = mv^2/r ------ 1

=> nw - w = mv°^2/r ------ 2

according to law of conservation of mass

=> v°^2 - v^2 = 4gr ...-------3

subtracting equation 1 from equation 2 we get ,

=> m(v°^2 - v^2) / r = nw - mw -2w ...

from 3

=> 4mg = (n-m)w - 2 mg ( since w = mg )

=> 6w = (n-m)w

=> n-m = 6

=> n=6+m

HENCE PROOVED

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