Question

A heavy spherical ball is constrained in a frame. the inclined surface is smooth. the maximum acceleration with which the frame can move without causing the ball to leave the frame is n/root3. Find the value of n.

Answer 1

Answer:

If we take the value of the reaction to be R from the inclined plane to the sphere then we will get the two components as Rcos60 and Rsin60.

The acceleration of the body is a and the weight of its own will be mg.

So, the value of Rcos60=ma.

Again the value of the another component Rsin60=mg.

On dividing the two equations we will get  the value of the tan60=g/a or the value of the a=g/tan60=g√3.

So, on comparing to the value of the question we will get the value of n=g.

Answer 2

when the sphere just move the rxn with the vertical wall will be zero .

by balancing the force in the frame reference of wedge.

let the rxn between the wedge and the sphere be NNcos60=maNsin60=mg

divide the eqn tan60=gaa=gtan60=g3√value of n=g