A heep of wheat in the form of corn diameter 10.5 and height 3m .find volume when it is covered by canvas find area
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For heap wheat
Diameter =10.5m
Radiues=10.5/2=5.25m
h=3m
Volume=1/3pi r^2h
=1/3 x22/7x) 5.25)^2x3
=86.625m
l=root r^2 + h^2
root )5.25)^2 + 3^2
root 27.5625+9
root 36.625
6.05m (approx)
CSA= pi r l
22/7 x 5.25 x 6.05 = 99.825 m^2
Hence the area of the canvas required = 99.825m^2 Ans
For heap wheat
Diameter =10.5m
Radiues=10.5/2=5.25m
h=3m
Volume=1/3pi r^2h
=1/3 x22/7x) 5.25)^2x3
=86.625m
l=root r^2 + h^2
root )5.25)^2 + 3^2
root 27.5625+9
root 36.625
6.05m (approx)
CSA= pi r l
22/7 x 5.25 x 6.05 = 99.825 m^2
Hence the area of the canvas required = 99.825m^2 Ans
immanualrajan1p3oky0:
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Answered by
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Dimensions of the conical shaped heap
Diameter = 10.5
radius = 5.25
1) volume of the heap = volume of the cone
V = (pi × r^2 × h ) / 3
= 22/7 × (5.25)^2 × 3 / 3
= 86.625 cm
2) let the slant height of the cone = L
l^2 = r^2 + h^2
l^2 = 3^2+5.25^2
l^2 = 9 + 27.5625
= 36.5625
therefore ,
L= 6.046
the area of canvas required to form rain
= C.S.A of cone
= pi.r.l
= 22/7 × 5.25 × 6.046
= 697.62/7
= 99.66 cm^2
plzz mark as brainliest answer !!!
Diameter = 10.5
radius = 5.25
1) volume of the heap = volume of the cone
V = (pi × r^2 × h ) / 3
= 22/7 × (5.25)^2 × 3 / 3
= 86.625 cm
2) let the slant height of the cone = L
l^2 = r^2 + h^2
l^2 = 3^2+5.25^2
l^2 = 9 + 27.5625
= 36.5625
therefore ,
L= 6.046
the area of canvas required to form rain
= C.S.A of cone
= pi.r.l
= 22/7 × 5.25 × 6.046
= 697.62/7
= 99.66 cm^2
plzz mark as brainliest answer !!!
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