Question

A height of at aquratral triangle masure 9cm find its area

Answer 1

$\textbf{Olá User!!}$
$\textbf{Here's your answer.}$

• Height of equilateral triangle = 9cm.

• Median of equilateral triangle,

=> √3/2 * side = Height

=> √3/2 * x = 9

=> x = (9*2)/√3

=> x = 18/√3

By rationalizing,

$= > x = \frac{18}{ \sqrt{3} } \times \frac{ \sqrt{3} }{\sqrt{3} }$

$= > x = \frac{18 \sqrt{3} }{ \sqrt{3} \times \sqrt{3} }$

$= > x = \frac{18 \sqrt{3} }{3}$

$= > x = 6 \sqrt{3}$

Again, Area of triangle = √3/4 * (side)²

$= > \frac{ \sqrt{3} }{4} \times {6 \sqrt{3} }^{2}$

$= > \frac{ \sqrt{3} }{4} \times 6 \times 6 \times 3$

$= > 27 \sqrt{3}$

$= > 27 \times 1.732$

$= > 46.764 \: cm^2$

Therefore, 46.76 cm² is the answer.

$\textbf{Hope it helps!!}$
$\textbf{@charlie16}$