A helicopter flying at a height of 200 m, with speed 20
m/s horizontally drops a bag. The magnitude of
displacement of bag after 5 s will be (g = 10 m/s2)
100 m
125 m
160 m
225 m
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Answered by
0
Answer:
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Explanation:
A helicopter flying at a height of 200 m, with speed 20
m/s horizontally drops a bag. The magnitude of
displacement of bag after 5 s will be (g = 10 m/s2)
100 m
125 m
160 m
225 m
Answered by
1
Displacement = 1/2at^2 + ut [(a=g)**]
Displacement = 1/2 x 10 x 5x 5 + (20x5)
Displacement = 125+100= 225 m
(These brackets used in a=g is used for explanation as acceleration due to gravity (g) is equal to acceleration (a).)
Hope this is correct. I don’t know if this is correct or not. You just check this question.
Displacement = 1/2 x 10 x 5x 5 + (20x5)
Displacement = 125+100= 225 m
(These brackets used in a=g is used for explanation as acceleration due to gravity (g) is equal to acceleration (a).)
Hope this is correct. I don’t know if this is correct or not. You just check this question.
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