Question

A helicopter has a cable hanging from it towards the sea below. A man of mass 80 kg rescues a child of mass 50,5kg . The two are attached to the cable and lifted from the sea to the helicopter. The lifting process consists of an initial uniform acceleration followed by a period of constant velocity and then completed by a final uniform deceleration. QUESTION: Calculate the tension in the cable during the period of a constant velocity of 2 m/s.

Answer 1

Resultant force F = ma

{Tension is upwards while the weight acts downwards. The resultant force / acceleration is upwards.}

T – 1280 = 130.5 × 0.57

Tension T = 1280 + 74.4 = 1350 N

(ii) Tension T = 1280 N

{For constant velocity, the resultant force is zero. Thus, tension = weight.}

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Answer 2

Here is your answer

. We have to calculate the tension in the cable during

period of constant velocity of 2m/s

. Tension T = 1280 N.

For constant velocity, the resultant force is zero.

. Thus, tension=weight.