Question

a helicopter is ascending vertically with a speed of 8.0m/s-¹. At a height of 12m above the earth,a package is dropped from the window. how much time does it take for the package take to reach the ground​

Answer 1

Explanation:

We know that if a body is dropped from another body moving vertically upwards,the velocity of the body = velocity of other body

there fore,

initial velocity,u = 8 m/s

height ,h = 12m

g = 10m/s

we know that ,

$time \: of \: descent = \sqrt{ \frac{2h}{g} }$

$= \sqrt{ \frac{24}{10} }$

$= 1.54s$

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