A helicopter is hovering at a point lying in the same vertical plane as two other points P and Q on the horizontal ground. Its distances from P and Q are 850 m and 1200 m respectively. Given that the angle of elevation from Q is 43 0, find PQ correct to 3 significant figures.
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Answer:
PQ= 1642.340 m
Step-by-step explanation:
Construct DA perpendicular to PQ
In triangle AQD
DQ= 850 m
then AQ= 850cos43°= 621.650 m
AD= 850sin43° = 579.698 m
Now to find AP we have to apply Pythagoras theorem in APD
PD^2 = AD^2+AP^2
1200^2=579.698^2+AP^2
AP= 1020.690 m
therefore, PQ= AP+ AQ
= 1020.690+621.650= 1642.340 m
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