a helicopter is rising up with a velocity of 5m/s a ball is projected from the helicopter vertically upwards with velocity v the ball crosses helicopter after 3 sec of projection find v
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A=5m/s,u=0,t=3,v=?
V=U+AT
V=0+5*3
V=15m/s
V=U+AT
V=0+5*3
V=15m/s
Answered by
1
Velocity of helicopter =5m/s
Velocity of ball when projected = v+5m/s
Now,if it stops after crossing helicopter final velocity = o
So, a=-10 m/s2 as its upward motion and gravity is downward
V=U + at
O = v+5 - 10x3
30=v+5
V=30-5 =25 m/s
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Velocity of ball when projected = v+5m/s
Now,if it stops after crossing helicopter final velocity = o
So, a=-10 m/s2 as its upward motion and gravity is downward
V=U + at
O = v+5 - 10x3
30=v+5
V=30-5 =25 m/s
If it helps u.. Plzz mark it brainliest..
ket66:
the answer is 15m/s
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