Question

A helicopter’s speed increases from 30 m/s to 40 m/s in 5 seconds. What is the acceleration of this helicopter?

Answer 1

$\large{\bf{\gray{\underline{\underline{\orange{Given:}}}}}}$

Initial speed = 30m/s

Final speed = 40m/s

Time interval = 5s

$\large{\bf{\gray{\underline{\underline{\green{To\:Find:}}}}}}$

We have to find acceleration of helicopter.

$\large{\bf{\gray{\underline{\underline{\pink{Solution:}}}}}}$

✻ Acceleration is defined as the rate of change of speed (velocity).

✻ It is a vector quantity having both magnitude as well as direction.

Unit : m/s²

Formula :

$\bigstar\:\underline{\boxed{\bf{\orange{a=\dfrac{v-u}{t}}}}}$

Let's solve it :)

$:\implies\tt\:a=\dfrac{v-u}{t}$

$:\implies\tt\:a=\dfrac{40-30}{5}$

$:\implies\tt\:a=\dfrac{10}{5}$

$:\implies\underline{\boxed{\bf{\gray{a=2\:ms^{-2}}}}}$

Answer 2

Given ,

Initial velocity (u) = 30 m/s

Final velocity (v) = 40 m/s

Time (t) = 5 sec

As we know that , the rate of change of velocity is called acceleration

It is denoted by " a "

$\boxed{ \tt{a = \frac{v - u}{t} }}$

It is vector quantity

Thus ,

a = (40 - 30)/5

a = 10/5

a = 2 m/s²

Therefore ,

• The acceleration of helicopter is 2 m/s²