Question

A helium atom has a diameter of approximately 9.8 • 10-11 meters. What is the diameter of a helium atom in nanometers?

Given unit: ________

Answer unit: ______

Solution: ______

Answer 1

Answer:

Hi mate Here's your Answer.

Step-by-step explanation:

Diameter = 9.8 ×10^-11

1m = 10^9 nm

Hence 9.8×10^-11m = 9.8×10^-11 × 10^9

= 9.8×10^-2

= 0.098nm

Hope you get it.

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Answer 2

The given question is A helium atom has a diameter of approximately 9.8 • 10-11 meters.

The size of the helium nucleus is about 1 Fermi or 1 FM,which is equivalent to 10 to the power -15 metre.

The atom is about 1 lakh times bigger than the nucleus with a size of 10 to the power 5 or 10 to the power -10.

We have to find what is the diameter of a helium atom in nanometres?

The value of the nanometre is 10 to the power of 9.

$10^{9}$

The given data is

diameter=$9.8*10^{-11}$ metres.

In order to express this in nanometre we have to multiply the given data with the value of nanometres,which is

$9.8*10^{-11}*10^{9}$

.On processing the power values we get,

$=10^{-11}*10^{9} \\=10^{-11+9} \\=10^{-2} nm$

The above value is obtained by the rule$10^{m} *10^{n} =10^{m+n}$

On proceeding we get$\frac{9.8}{10^{2} } \\=\frac{9.8}{100} \\=0.098 nm$.

Therefore,the final answer is 0.098nm

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