Question

A helium balloon containing 5m³ of gas at a pressure of 30kPa is released into the air. Assuming that the temperature is constant calculate the volume the balloon would have when the pressure inside the balloon has fallen to 5kPa. Answer in m³.

Answer 1

Answer:

30m³

Explanation:

pV = constant

5 x 30 = constant

constant = 150

pressure = constant/volume

rearrange the equation to get:

volume = constant/pressure

volume = 150/5

volume = 30m³

Answer 2

The temperature remains constant throughout.

According to this BOYLE's law can be applied.

Boyle's law states that if the temperature remains constant then:

$Pressure(P)\times Volume(V)= constant$

Then,$P_{1}V_{1} =P_{2} V_{2}$

Given, P₁=$30kPa$

          V₁=$5 m^{3}$

          P₂=$5kPa$

          V₂=$?$

Applying Boyle's law⇒

$P_{1}V_{1} =P_{2} V_{2}\\30kPa\times 5m^{3} =5kPa\times V_{2}\\V _{2} =30m^3}$

Hence, the volume the balloon would have when the pressure inside the balloon has fallen to 5kPa is 30m³.