Question

A helium nucleus has a charge 2e and a neon nucleus 10e with what force do they repel
other when seperated by 3 milli micron?
​

Answer 1

Given

$q=1.6 * 10^{-19}$

$d=3 \ milli micron\ =3 * 10^{-9}\ m$

$q1 = 2e\ \\ q2 = 10 e$

To find :

F=?

Solution :

We know that force between the two charges can be find by using that formula

$F=\ \frac{k* q1 * q2}{d^{2} }$

Where q1, q2 are the charges d is the separation between the two charges and k is Coulomb constant .

Putting these value in the previous equation

$F=\ \frac{9 * 10^{9} * 2* 10 * 1.602 *10^{-19} *\ 1.602 * 10^{-19} }{ 3 *10^{-9} *\ 3*10^{-9} }$

On solving these value we get

$51.33 * 10^{-11} N$