Question

a Helium nucleus makes a full rotation in a circle of radius 0.8 m in 2s the value of the magnetic field will be​

Answer 1

Answer:

Bhai Itna Padhai Matt Kar Nhi Gadha Bann Jayega

Answer 2

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The current due to the revolution of the HE nucleus is I = qω/2π = 2×1.6×10^-19/2

=> 1.6×10^-19 A

Magnetic field at the centre B = μ0I/2r

=> μ0×1.6×10^-19/2×0.8

=> 10^-19μ0