A hemi_spherical bowl haveing 4adius 2.8cm ,find its curved surface area and volume.
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Answered by
2
Answer:
..............
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Answered by
0
Answer:
Step-by-step explanation:
csa = 2πr²
= 2 × 22/7 × 2.8 × 2.8
= 2 × 22 × 0.4 × 2.8
= 49.28 cm²
volume = 2/3 πr³
= 2/3 × 22/7 × 2.8 × 2.8 × 2.8
= 2/3 × 22 × 0.4 × 2.8 × 2.8
= 45.99 cm³
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