A hemisperical decorative block is shown which is made of 2 solids,a cube with 6 cm and a hemisphere fixed on the top has a diameter of 4.2 cm. Find t.s.a of block and volume of the block.pi = 22/7
Answers
Answer:
Step-by-step explanation:
The decorative block is a combination of a cube and the hemisphere.
For cubical portion:
Each edge= 5 cm
For hemispherical portion:
Diameter= 4.2 cm
Radius(r)= 4.2/2= 2.1 cm
Total surface area of the cube= 6 × (edge)²
= 6 (5)²= 6 × 25= 150 cm²
Here the part of the cube where the hemisphere is attached is not included in the surface area.
So the total surface area of the decorative block= total surface area of the cube+ area of base of hemisphere + curved surface area of hemisphere
total surface area of the decorative block= 150 - πr² + 2πr²
= 150 +πr²
= 150 + (22/7) × 2.1× 2.1
= 150 + 13.86 = 163.86cm²
Hence,total surface area of the decorative block=163.86 cm²
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A hemisperical decorative block is shown which is made of 2 solids,a cube with 6 cm and a hemisphere fixed on the top has a diameter of 4.2 cm. Find t.s.a of block and volume of the block.pi = 22/7
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