Question

a hemisphere boule is made upnof stell,0.25cm thick .the inner radius of the boule is 5cm .finde the outer curved surface area of the boule (assumeπ=22/7)m​

Answer 1

Answer :-

• CSA of Bowl = 173.25 cm²

Given :-

• Thickness of Bowl = 0.25 cm
• Inner Radius of Bowl = 5 cm

To Find :-

• CSA of Bowl = ?

Explanation :-

In order to find the Outer CSA of the Bowl, First we need to find the Outer Radius of the Bowl.

$\blue { \boxed { \bf \bigstar \: Outer \: Radius = Thickness + Inner \: Radius \: \bigstar }}$

$\rm \hookrightarrow Outer \: Radius = (0.25 + 5) \: cm = \bold{5.25 \: cm}$

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As we Know,

$\orange { \boxed { \bf \bigstar \: CSA \: of \: Hemisphere = 2 \pi r^2 \: \bigstar }}$

$\rm \hookrightarrow \: 2 \pi r^2 = Outer \: CSA \: of \: Bowl$

$\rm \hookrightarrow \: 2 \times \dfrac{22}{7} \times (5.25)^2$

$\rm \hookrightarrow \: 2 \times \dfrac{22}{7} \times 5.25 \times 5.25$

$\rm \hookrightarrow \: 2 \times 22 \times 0.75 \times 5.25$

$\rm \hookrightarrow \: 44 \times 3.9375$

$\red { \underline { \boxed { \bf \hookrightarrow \: 173.25 \: cm^2 }}}$

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Hence, the Outer CSA of the Hemispherical Bowl is 173.25 cm².