A hemisphere bowl has a radios of its rim equal to 4.2cm find the total capacity of 30 such bowl
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Answered by
13
Given ;
Radius = r = 4.2 cm
Total capacity of a bowl
= Volume of the hemisphere
= Volume of Sphere/2
= (4/3)πr^3 ÷ 2
= (2/3)πr^3
= (2/3) × (22/7) × (4.2×4.2×4.2)
= 155.232 cubic cm
--------------------------------------
Volume of 30 such bowl
= 30×volume of one bowl
= 30×155.232
= 4656.96 cubic cm
========================
Radius = r = 4.2 cm
Total capacity of a bowl
= Volume of the hemisphere
= Volume of Sphere/2
= (4/3)πr^3 ÷ 2
= (2/3)πr^3
= (2/3) × (22/7) × (4.2×4.2×4.2)
= 155.232 cubic cm
--------------------------------------
Volume of 30 such bowl
= 30×volume of one bowl
= 30×155.232
= 4656.96 cubic cm
========================
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Answered by
2
Total capacity of 30 hemisphrical bowls=30*( Volume of 1 such bowl)
Volume of 30 hemispherical bowls=30*2/3Πr³
=10*2*22/7*4.2*4.2*4.2
=440*74.088/7
=440*10.584
=4656.96 cm³
Total capacity=4.65696 litres.
Volume of 30 hemispherical bowls=30*2/3Πr³
=10*2*22/7*4.2*4.2*4.2
=440*74.088/7
=440*10.584
=4656.96 cm³
Total capacity=4.65696 litres.
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