Question

A hemisphere bowl has a radius of 3.5 cm . what would be the volume of water it would contain?
a. 85.6 cm
b. 91.8 cm
c. 80.4 cm
d. 89.8 cm​

Answer 1

The volume of water the bowl can contains = Volume of hemisphere

=

3

2

πr

3

=

3

2

×

7

22

×3.5×3.5×3.5cm

3

=89.8cm

3

(approx)

Answer 2

Answer:

d)89.8 cubic cm

Step-by-step explanation:

$volume \: of \: hemisphere \: = \frac{2\pi {r}^{3} }{3} \\ = \frac{2 \times 22 \times 3.5 \times 3.5 \times 3.5}{7 \times 3} \\ = 89.83 {cm}^{3}$

I hope you are clear if not just comment and don't forget to mark my answer as the brainliest.