Question

a hemisphere bowl is made of brass has inner diameter 10.5cm .find the cost of TIN plating it on the inside area of bowl.???

Answer 1

Inner Radius of the bowl = 10.5/2 = 5.25 cm

So, the area of inner part of the bowl = 2πr^2

A = 2 × 3.14 × 5.25 × 5.25

A = 173.09 m^2......●

For cost you have to mention the cost of 1 m^2 plating, which will be surely mentioned in the question.


So, the cost of tin plating = Cost of plating of 1 m^2 area × 173.09

That will be the cost.

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Hope it was helpful.

Answer 2

hemisphere=
$2\pi d$
2*3.14*10.5
=65.94 cm^2

Cost of it is not given so couldn't find it.
hope it helps you.